When you deposit money in a bank, the bank usually pays you for the use of your money. When you take out a loan from a bank, you have to pay the bank for the use of their money. In both cases, the money paid is called the interest. It is usually expressed as a percent. Here we shall look at a formula for simple interest.
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The following table gives the Formulas for Simple Interest, Compound Interest, and Continuously Compounded Interest. Scroll down the page for more examples and solutions.
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The Simple Interest Formula is given by
Simple Interest = Principal × Interest Rate × Time
I = Prt where
The Principal (P) is the amount of money deposited or borrowed.
The Interest Rate (r) is a percent of the principal earned or paid.
The Time (t) is the length of time the money is deposited or borrowed.
Example:
Sarah deposits $4,000 at a bank at an interest rate of 4.5% per year. How much interest will she earn at
the end of 3 years?
Solution:
Simple Interest = 4,000 × 4.5% × 3 = 540
She earns $540 at the end of 3 years.
Example:
Wanda borrowed $3,000 from a bank at an interest rate of 12% per year for a 2-year period. How much
interest does she have to pay the bank at the end of 2 years?
Solution:
Simple Interest = 3,000 × 12% × 2 = 720
She has to pay the bank $720 at the end of 2 years.
Example:
Raymond bought a car for $40, 000. He took a $20,000 loan from a bank at an interest rate of 15% per
year for a 3-year period. What is the total amount (interest and loan) that he would have to pay the
bank at the end of 3 years?
Solution:
Simple Interest = 20,000 × 13% × 3 = 7,800
At the end of 3 years, he would have to pay
$20,000 + $7,800 = $27,800
Examples:
Interest represents a change in money.
If you have a savings account, the interest will increase your balance based upon the interest rate paid by the bank.
If you have a loan, the interest will increase the amount you owe based upon the interest rate charged by the bank.
Examples:
Examples:
Examples Of Simple Interest Problems:
Examples Of Compound Interest Problems:
Examples Of Continuously Compound Interest Problems:
Example Of Effective Rate Of Return:
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