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Rate, Time, Distance
Solving Speed, Time, Distance Problems Using Algebra
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Math Worksheets
These lessons, with videos, examples and step-by-step solutions, explain how to solve time-distance-rate problems. In this lesson, we will explain how to solve distance problems that involve round trips.
Distance problems are word problems that involve the distance an object will travel at a certain average rate for a given period of time. These problems can also involve an object traveling to a destination and returning. The goal is to find the total distance, time, or average speed.
The formula for distance problems is: distance = rate × time or d = r × t.
It would be helpful to use a table to organize the information for distance problems.
The following diagram shows how to set up a Rate-Time-Distance (RTD) table to help solve time-distance problems. Scroll down the page for more examples and solutions on how to solve distance problems.
Key Points for Round Trip Problems:
The following diagram gives the steps to solve a round-trip distance problem.
Types of Distance Word Problems:
Travel in Same Direction
Travel in Opposite Directions
Round Trip Problems
Average Speed Problems
Wind/Current Problems
Printable & Online Algebra Worksheets
Example:
John took a drive to town at an average rate of 40 mph. In the evening, he drove back at 30 mph. If he spent a total of 7 hours traveling, what is the distance traveled by John?
Solution:
Step 1: Set up a rtd table.
r |
t |
d |
|
Case 1 |
|||
Case 2 |
Step 2: Fill in the table with information given in the question.
John took a drive to town at an average rate of 40 mph. In the evening, he drove back at 30 mph. If he spent a total of 7 hours traveling, what is the distance traveled by John?
Let t = time to travel to town.
7 – t = time to return from town.
r |
t |
d |
|
Case 1 |
40 |
t |
|
Case 2 |
30 |
7 – t |
Step 3: Fill in the values for d using the formula d = rt
r |
t |
d |
|
Case 1 |
40 |
t |
40t |
Case 2 |
30 |
7 – t |
30(7 – t) |
Step 4: Since the distances traveled in both cases are the same, we get the equation:
40t = 30(7 – t)
Use distributive property
40t = 210 – 30t
Isolate variable t
40t + 30t = 210
70t = 210
Step 5: The distance traveled by John to town is
40t = 120
The distance traveled by John to go back is also 120
So, the total distance traveled by John is 240
Answer: The distance traveled by John is 240 miles.
Distance, Rate, Time Word Problems
Two examples of distance, rate, and time. One involves adding the distances in our chart, where as the other example involves setting the distances equal to each other.
Distance-time word problem where the total time is given
Example:
Gordon rode his bike at 15 mph to go get his car. He then drove back at 45 mph. If the entire trip took him 8 hours, how far was his car?
Check out many other Algebra Word Problems
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